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12.36x^2+x-2.00=0
We add all the numbers together, and all the variables
12.36x^2+x-2=0
a = 12.36; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·12.36·(-2)
Δ = 99.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{99.88}}{2*12.36}=\frac{-1-\sqrt{99.88}}{24.72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{99.88}}{2*12.36}=\frac{-1+\sqrt{99.88}}{24.72} $
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